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6x^2+4.5x=5292
We move all terms to the left:
6x^2+4.5x-(5292)=0
a = 6; b = 4.5; c = -5292;
Δ = b2-4ac
Δ = 4.52-4·6·(-5292)
Δ = 127028.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.5)-\sqrt{127028.25}}{2*6}=\frac{-4.5-\sqrt{127028.25}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.5)+\sqrt{127028.25}}{2*6}=\frac{-4.5+\sqrt{127028.25}}{12} $
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